matlab ,THETA and RHO must be the same size.>> theta = -pi/2:pi/10:pi/2;>> gain=abs((sin(4*theta)/(4*theta)));>> polar (theta,gain,'r-');Error using polar (line 61)THETA and RHO must be the same size.

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/14 09:03:29
matlab ,THETA and RHO must be the same size.>> theta = -pi/2:pi/10:pi/2;>> gain=abs((sin(4*theta)/(4*theta)));>> polar (theta,gain,'r-');Error using polar (line 61)THETA and RHO must be the same size.

matlab ,THETA and RHO must be the same size.>> theta = -pi/2:pi/10:pi/2;>> gain=abs((sin(4*theta)/(4*theta)));>> polar (theta,gain,'r-');Error using polar (line 61)THETA and RHO must be the same size.
matlab ,THETA and RHO must be the same size.
>> theta = -pi/2:pi/10:pi/2;
>> gain=abs((sin(4*theta)/(4*theta)));
>> polar (theta,gain,'r-');
Error using polar (line 61)
THETA and RHO must be the same size.

matlab ,THETA and RHO must be the same size.>> theta = -pi/2:pi/10:pi/2;>> gain=abs((sin(4*theta)/(4*theta)));>> polar (theta,gain,'r-');Error using polar (line 61)THETA and RHO must be the same size.
gain=abs((sin(4*theta)./(4*theta)));
|
注意这里的除法要用 ./

matlab ,THETA and RHO must be the same size.>> theta = -pi/2:pi/10:pi/2;>> gain=abs((sin(4*theta)/(4*theta)));>> polar (theta,gain,'r-');Error using polar (line 61)THETA and RHO must be the same size. 在matlab中theta=[0:0.01:2*pi]';是什么意思 matlab里cos(theta)'什么意思那个’呢 在MATLAB中该怎么利用成程序解F=K*theta/((a+0.5*l)*sin(pi-theta))中的theta表达式 matlab中theta是什么意思matlab中的函数theta = (0:179)';[R,xp] = radon(edge(gray_image),theta)中的theta是什么意思?有什么意义?期待达人的帮助. Matlab数值积分问题一个函数E(theta,phi)vl1=[0,cos(pi/4),sin(pi/4)]vl2=[0,-cos(pi/4),sin(pi/4)]vtheta=[cos(theta)*cos(phi),cos(theta)*sin(phi),-sin(theta)]vphi=[-sin(phi),cos(phi),0]vr=[sin(theta)*cos(phi),sin(theta)*sin(phi),cos(theta)]n Matlab出现is not a valid expression or equation.clear;syms theta x;solve('9.8*x*x/(tan(theta)*tan(theta))-(2*240000*(sqrt(7)-sqrt(4*cos(theta)+5))-196*(25+100)*(sin(theta)-sqrt(3)/2))*x/((1/3*5+100)*tan(theta))+9.8*x*x-2*10*sin(theta)*(240000*(sqrt matlab 已知 r ^2 = a ^2 *cos (theta) x =r*cos( theta) y = r*sin (theta) 怎么 将 等式里的r 和 theta 换成 x y matlab 符号常量n = 200;theta = 0.3;for i=1:n;x=0:0.01:i;theta=0.3;y=(1-1/sqrt(1-theta^2)*exp(-theta*x).sin(sqrt(1-theta^2)*x+acos(theta));plot(x,y)axis([0,20,0,1.5]);M(i)=getframe;endmovie(M,3)%为什么提示 y=(1-1/sqrt(1-theta^2)*exp(-theta*x) matlab中极坐标弧度theta,默认范围是什么从哪个轴,什么方向开始算的 MATLAB中命令po12cart什么意思? 例如:[x,y]=po12cart(theta,rho) 求这个表达式G值完整matlab代码,表达式如图所示 S范围(0,1),theta范围(0,2*pi)同时输出s, theta和G的值 matlab中x=theta(P(:,尤其是那个(:,2)是表示什么啊,其中theta是角度,P是坐标 MATLAB for m=2:16;theta(m,1)=theta(m-1,1)+(pi/180)*(360/16) 实现的结果是什么 matlab 中间的积分求解不出来 v2 =exp(-2*u*theta)*Int(-1/2*g*(-12*a^4*b^2*cos(4*theta)+12*a^4*b^2+20*a^6+20*b^6-12*a^2*b^4*cos(4*theta)+12*a^2*b^4+6*a^2*b^4*cos(2*theta)-6*a^4*cos(2*theta)*b^2+6*a^4*b^2*cos(6*theta)-6*a^2*b^4*cos(6*theta)-30* matlab三角函数方程求解变量为theta,方程为:b*b*c*c=a*a*(cos(theta)^2*c^2-sin(theta)^2*b^2)其中a,b,c为已知量 matlab中,这个程序错在哪?clc clear alllamada=0.2;theta=0.7;s=0:0.01:1;c=lamada*s+3/2;f=s.^2*lamada.^2/(4*theta)+(1/2)*(-lamada*c/theta+lamada)*s+c.^2/(4*theta)-c/2+theta/8+1/8;plot(s,f,'b');程序提醒f函数错了 matlab中要求向量n1和n2的叉乘,但n1中有个数组变量,所以cross(n1,n2)出错size不一样,theta=0:0.1*pi:2*pi;x=(r-t)*cos(theta);y=(r-t)*sin(theta);z=sqrt(R^2-((r-t).*sin(theta)-e).^2)./sin(alpha)-(r-t).*cos(theta)./tan(alpha)