作业帮#define SUB(a) (a)-(a) main() { int a=2,b=3,c=5,d;d=SUB(a+b)*c; printf("%d\n",d); }
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#define SUB(a) (a)-(a) main() { int a=2,b=3,c=5,d;d=SUB(a+b)*c; printf("%d\n",d); }
#define SUB(a) (a)-(a) main() { int a=2,b=3,c=5,d;
d=SUB(a+b)*c;
printf("%d\n",d);
}
#define SUB(a) (a)-(a) main() { int a=2,b=3,c=5,d;d=SUB(a+b)*c; printf("%d\n",d); }
d=SUB(A+B)*C //a=a+b
d=(a+b)-(a+b)*c //没有括号把前面括起来,因为这是define定义的宏的特点
d=5-5*5=-20
C语言中：#define SUB(a) (a)-(a)
#define SUB(a) (a)-(a)什么意思定义了这个宏以SUB(c+b)×d应该怎么运算?
#define SUB(a) (a)-(a) main() { int a=2,b=3,c=5,d;d=SUB(a+b)*c; printf(%d
,d); }
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