2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y

来源：学生作业帮助网编辑：作业帮时间：2024/04/28 21:44:06

2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y
2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y

2x-y=2,求[(x²+y²)-(x-y)²+2y(x-y)]÷4y
先化简[(x²+y²)-(x-y)²+2y(x-y)]/4y
[(x²+y²)-(x-y)²+2y(x-y)]/4y
=[x²+y²-(x²+y²-2xy)+2xy-2y²]/4y
=[x²+y²-x²-y²+2xy+2xy-2y²]/4y
=[4xy-2y²]/4y
=[4x-2y]/4
=2*(2x-y)/4
=(2x-y)/2
=1

2x-y=2,
[(x²+y²)-(x-y)²+2y(x-y)]÷4y
=(2xy+2xy-2y²)÷4y
=(2x-y)/2
=2/2
=1

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