sinx+sinb+sin91度=0 ,cosx+cosb+cos91度=0,求cos(x-b)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/02 22:55:53
sinx+sinb+sin91度=0 ,cosx+cosb+cos91度=0,求cos(x-b)

sinx+sinb+sin91度=0 ,cosx+cosb+cos91度=0,求cos(x-b)
sinx+sinb+sin91度=0 ,cosx+cosb+cos91度=0,求cos(x-b)

sinx+sinb+sin91度=0 ,cosx+cosb+cos91度=0,求cos(x-b)
cos(x-b)=cosxcosb+sinxsinb
又sinx+sinb=-cos1du,cosx+cosb=sin1du,(-cos1du)平方+(sin1du)平方=1
所以(sinx+sinb)平方+(cosx+cosb)平方=sinx平方+cosx平方+sinb平方+cosb平方+2(sinxsinb+cosxcosb)=2+2(sinxsinb+cosxcosb)=2+2cos(x-b)=1
所以cos(x-b)=-0.5