已知x(x-1)-(x2-y)=-2,求(x2+y2)除2-xy的值.

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已知x(x-1)-(x2-y)=-2,求(x2+y2)除2-xy的值.

已知x(x-1)-(x2-y)=-2,求(x2+y2)除2-xy的值.
已知x(x-1)-(x2-y)=-2,求(x2+y2)除2-xy的值.

已知x(x-1)-(x2-y)=-2,求(x2+y2)除2-xy的值.
x²-x-x²+y=-2
-x+y=-2
x-y=2
(x²+y²)/2-xy
=(x²-2xy+y²)/2
=(x-y)²/2
=(2)²/2
=4/2
=2

x(x-1)-(x2-y)=-2 得 y - x = -2 则 x - y = 2 (x - y)=4
展开得:x2+y2 -2xy=4 则 xy= [4-(x2+y2)]/2 带入(x2+y2)/(2-xy)得 2