先化简,再计算：(x^2-y^2)/(x-y)-2x+y,其中x=3,y=2

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先化简,再计算：(x^2-y^2)/(x-y)-2x+y,其中x=3,y=2
先化简,再计算：(x^2-y^2)/(x-y)-2x+y,其中x=3,y=2

先化简,再计算：(x^2-y^2)/(x-y)-2x+y,其中x=3,y=2
答案等于1.原始化简为(-x^2-2y^2+3xy)/(x-y)=(3xy-3y^2)/(x-y)+(y^2-x^2)/(x-y)=2y-x=1

(x^2-y^2)/(x-y)-2x+y
=(x+y)(x-y)/(x-y)-2x+y
=x+y-2x+y
=2y-x
=2x2-3
=1

(x^2-y^2)/(x-y)-2x+y
=(x+y)(x-y)/(x-y)-2x+y
=x+y-2x+y
=-x+2y
当x=3，y=2，得到原式=-3+4=1

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