7.[2pt]The curve in the energy diagram shows the potential energy,U(x),of a particle as a function of its position,x.The total energy of the particle,E,is constant (the horizontal line above the curve).The grid is divided into squares that are 5 J hi

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7.[2pt]The curve in the energy diagram shows the potential energy,U(x),of a particle as a function of its position,x.The total energy of the particle,E,is constant (the horizontal line above the curve).The grid is divided into squares that are 5 J hi

7.[2pt]The curve in the energy diagram shows the potential energy,U(x),of a particle as a function of its position,x.The total energy of the particle,E,is constant (the horizontal line above the curve).The grid is divided into squares that are 5 J hi
7.[2pt]
The curve in the energy diagram shows the potential energy,U(x),of a particle as a function of its position,x.The total energy of the particle,E,is constant (the horizontal line above the curve).The grid is divided into squares that are 5 J high and 1 m wide.
For each horizontal position x1,...,x8 (corresponding to the points on the U(x) curve),select the correct value for the force on the particle at that position.E.g.,if the force on the particle at x1 is 15 N to the left,at x2,5 N to the left,and at positions x3,...,x8,0 N,enter ACBBBBBB.
A)\x0515 N to the left\x05B)\x050 N
C)\x055 N to the left\x05D)\x055 N to the right
E)\x0510 N to the left\x05F)\x0515 N to the right
G)\x0510 N to the right

7.[2pt]The curve in the energy diagram shows the potential energy,U(x),of a particle as a function of its position,x.The total energy of the particle,E,is constant (the horizontal line above the curve).The grid is divided into squares that are 5 J hi
英文2的大b致意思是：用一k根长7为3L的绳连着一o个b质量为3m的球,让它在竖直平面内3做自由圆周运动,（最高点也z可以4通过）问下u面六5个h哪些正确（T),哪些错误（F) 2.F（Tt和Vt分3别为6最高点的绳的拉力m和速度.mvt2.L = Tt+mvt2.L = Tt?mg） 2,T（在圆周最底部的速度自然大i于j最高点的速度,因为0除了u重力y之y外没有任何力k作用于q这个v绳和球构成的系统,由最高点到最低点重力j势能转化1为0动能,故动能增大k） 2.T（最高点T=mvt2.L -mg,最低点Tb=mv2.L +mg,v>vt) 5.F,（最高点T=mvt2.L -mg,最低点Tb=mv2.L +mg,v>vt) 3.F（加速度方4向指向圆心3,故应该向下o） 0.F（最高点的T=mvt2.L -mg,故没法和重力z比6较大o小u最高点mVt2=Tt+mg 最低点mV2=Tb-mg mg*2L=0.7mV2-0.5mVt2 联合上z面三a式求解得 Tb-Tt=2mgL-2mg=3*0.86*70*0.20-2*0.17*60=2.03N
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