作业帮英文化学题,感觉题的几个选项都不对吧?What volume of sodium hydroxide solution of concentration0.10 mol dm-3 would be needed to neutralize 25 cm3 of a solution of sulphuric acid of concentration 0.25 mol dm-3?A.25 cm3B.50 cm3C.62.5 cm3
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英文化学题,感觉题的几个选项都不对吧?What volume of sodium hydroxide solution of concentration0.10 mol dm-3 would be needed to neutralize 25 cm3 of a solution of sulphuric acid of concentration 0.25 mol dm-3?A.25 cm3B.50 cm3C.62.5 cm3
英文化学题,感觉题的几个选项都不对吧?
What volume of sodium hydroxide solution of concentration
0.10 mol dm-3 would be needed to neutralize 25 cm3 of a solution of sulphuric acid of concentration 0.25 mol dm-3?
A.
25 cm3
B.
50 cm3
C.
62.5 cm3
D.
67.5 cm3
E.
130 cm3
英文化学题,感觉题的几个选项都不对吧?What volume of sodium hydroxide solution of concentration0.10 mol dm-3 would be needed to neutralize 25 cm3 of a solution of sulphuric acid of concentration 0.25 mol dm-3?A.25 cm3B.50 cm3C.62.5 cm3
同感,没有正确答案!
先确认一下有没有翻译错：
多少摩尔的0.10mol/dm³的氢氧化钠溶液可以中和25cm³的0.25mol/dm³硫酸溶液?
n(H2SO4)=0.25*0.025=0.00625mol
2mol的NaOH可以中和1mol的H2SO4
所以：n(NaOH)=2n(H2SO4)=0.00625mol*2=0.0125mol
V(NaOH)=(0.0125mol)/(0.0001mol/cm³)=125cm³
没有正确答案
V=25*0.25*2/0.1=125cm3
答案应该是125cm3。求需要多少体积的0.1mol/l的NaOH才能中和0.25mol/l的硫酸25cm3
0.1×V=2×25×0.25，解之得，v=125