作业帮{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
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{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
(x+y)/2+(x-y)/3=1,则3(x+y)+2(x-y)=6①
(x+y)-5(x-y)=2②
①×5＋②×2,得15(x+y)+2(x+y)=30+4,解得x+y=2③
代入①,解得x-y=0④
③+④,解得x=1,y=1
先解关于x+y,x-y的方程组
x+y=2
x-y=0
所以x=1，y=1
(x+y)/2+(x-y)/3=1 3(x+y)+2(x-y)=6 5x+y=6.......1
(x+y)-5(x-y)=2 6y-4x=2 ......................................2
1式×6-2式 可得 x=1
代入1式 得y=1
X=1，Y=1
(x+y)/2+(x-y)/3=1,(x+y)+2(x-y)/3=2
(x+y)-5(x-y)=2
2(x-y)/3=-5(x-y)
x-y=0 x=y
(x+y)/2+(x-y)/3=1,15(x+y)/2+5(x-y)=15
(x+y)-5(x-y)=2
x+y=2
x=y=1
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