main() {int m=3,n=4,x; x=-m++; x=x+8/++n; print("%d\n",x);} 运行结果是

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/14 05:48:09
main() {int m=3,n=4,x; x=-m++; x=x+8/++n; print(

main() {int m=3,n=4,x; x=-m++; x=x+8/++n; print("%d\n",x);} 运行结果是
main() {int m=3,n=4,x; x=-m++; x=x+8/++n; print("%d\n",x);} 运行结果是

main() {int m=3,n=4,x; x=-m++; x=x+8/++n; print("%d\n",x);} 运行结果是
-2
理由:
首先 x=-m++;这一步 令 x= -m 也就是x=-3
然后 x=x+8/++n
先 ++n 使n=5
然后 8/n 取整 = 1
最后 x+1 = -2
最后结果是 x=-2
显示为
-2

#define N 20 fun(int a[],int n,int m) {int i; for(i=m;i>n;i--)a[i+1]=a[i]; return m; } void main() #define N 20fun(int a[],int n,int m){int i;for(i=m;i>n;i--)a[i+1]=a[i];return m;}void main(){ int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,0,N/2);for(i=0;i #include stdio.hint fun (int k,int *m){if (k%3) *m=k*k;else *m=k/3;}main(){int (*p) (int,int *),m;p=fun;(*P) (78,&m);printf ( %d ,m);} main() { int n=4; while(n--) printf(%d,--n); } #include int gcd(int m,int n) { if(m%n==0) printf(%d ,n); else gcd(n,m%n); } main() { i#includeint gcd(int m,int n){if(m%n==0) printf(%d ,n);elsegcd(n,m%n);} main(){int m,n;scanf(%d%d,&m,&n);printf(%d,gcd(n,m%n));}求m整除n 计算1-2+3-4+……+/-n的C++程序int main(){int sum(int);int n;coutn;if (n%2==0)cout main(){int m=3,n=4,x; x=-m++; x=x+8/++n; printf(%d ,x);} 程序运行后的结果是多少? void main() {int m=3,n=4,x; x=-m++; x+=8/++n; printf(%d ,x); } main() {int m=3,n=4,x; x=-m++; x=x+8/++n; print(%d ,x);} 运行结果是 C语言一道题目.不知道哪里出错了,#includeint main(){int b[3][4];int i,j,max,m,n;for(i=0;i #includeint a(int x);int b(int y);int main(){int m,n;n=6;m=a(n);printf(%d ,m);return 0;}int a(int x){x=b(x+3);return x;}int b(int y){return y+1;} #include void f(int *p,int*q); main() {int m=1,n=2,*r=&m; f(r,&n);printf(%d,%d,m,n);}#include void f(int *p,int*q);main(){int m=1,n=2,*r=&m;f(r,&n);printf(%d,%d,m,n);}void f(int *p,int *q){p=p+1;*q=*q+1;}运行后的结果是A 1,3 B 1,2 说说为 main() { int i=3,m ; m=(i++)+(++i)+(++i)+(++i)+(i++); printf( %d ,m); } #define N 20 fun(int a[],int n,int m) { int i; for(i=m;i>=n;i--) a[i+1]=a[i]; return a[a+1]; } main#define N 20fun(int a[],int n,int m){ int i;for(i=m;i>=n;i--)a[i+1]=a[i];return a[a+1];}main(){int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,2,9);for(i=0;i 下列程序的输出结果是#define N 20void fun (int a[ ],int n,int m){int i,j;for (i=m;i>n;i--)a[i+1]=a[i];}main(){int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,2,9);for(i=0;i 为什么输入1得到了2 百思不得其解!//#include int math(n){if (n>=3)return math(n-1)+math(n-2);else if(n=2)return 2;else if(n=1)return 1;}int sum (int n){int m=0;for (;n>0;n--){m+=math(n);}return m;}main(){int i=0;printf(30个数和为:% #includestruct st{int i;int j;} *p;void main(){struct st m[]={{10,1},{20,2},{30,3}};p=m;printf(%d/n,(*++p).j);} #include int call(int s[],int y) { static int t=3; y=s[t--]; return(y); } void main() { in#includeint call(int s[],int y){static int t=3;y=s[t--];return(y);}void main(){int a[]={3,8,4,2},n,x=0;for(n=0;n #include int gcd(int m,int n) { if(m%n==0) printf(%d ,n); else gcd(n,m%n); } main() { i#includeint gcd(int m,int n){if(m%n==0) printf(%d ,n);elsegcd(n,m%n);} main(){int m,n;scanf(%d%d,&m,&n);printf(%d,gcd(n,m%n));}求m/n整除 程序有错