已知函数f(x)=sin(wx+φ),其中w>0,|φ|

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已知函数f(x)=sin(wx+φ),其中w>0,|φ|
已知函数f(x)=sin(wx+φ),其中w>0,|φ|

已知函数f(x)=sin(wx+φ),其中w>0,|φ|
------------cosπ/4cosφ-sin（3π/4)sinφ=0
因为sin(π-φ)=sinφ
所以sin(π-π/4)=sin(π/4)
--------------------------------cosπ/4cosφ-sinπ/4sinφ=0
--------------------------------cos(π/4+φ)=0

(cosπ/4cosφ) -sin（3π/4)*sinφ=0
(cosπ/4cosφ)-(sinπ/4sinφ)=0
cos(π/4+φ)=0

由cos(π/4)cosφ-sin（3π/4)sinφ=0，又sin（3π/4)=sin（π-3π/4)=sin（π/4)，则原式可化为cos(π/4)cosφ-sin(π/4)sinφ=0,则有cos(π/4+φ)=0
即cosπ/4cosφ-sin（3π/4)sinφ=cos(π/4)cosφ-sin(π/4)sinφ
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