设x=log23,求2ˆ2x+2ˆ-2x+2 / 2ˆx+2ˆ-x

设x=log23,求2ˆ2x+2ˆ-2x+2 / 2ˆx+2ˆ-x
设x=log23,求2ˆ2x+2ˆ-2x+2 / 2ˆx+2ˆ-x

设x=log23,求2ˆ2x+2ˆ-2x+2 / 2ˆx+2ˆ-x
x=log23
那么：2^x=3
2ˆ2x+2ˆ-2x+2 / 2ˆx+2ˆ-x
=3²+(1/3)²+2/3+1/3
=9+1/9+1
=10又1/9

2^x=3
2ˆ2x+2ˆ-2x+2 / 2ˆx+2ˆ-x
=3*3+(1/3)^2+2/3+1/3
=10+1/9
=91/9

x=log23
2^x=3
2ˆ2x+2ˆ-2x+2 / 2ˆx+2ˆ-x
=(2^x+2^-x)^2/ 2ˆx+2ˆ-x
= 2ˆx+2ˆ-x
=3+1/3
=3又1/3