[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程

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[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程
[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程

[x+y/2=z+x/3=y+z/4,x+y+z=27]要有过程
12x+6y=12z+4x=12y+3z
分成两个等式:
x+y/2 = y+z/4
=>4x+2y= 4y+z
=>4x=2y+z(一）
x+y/2=z+x/3
=>6x+3y = 6z +2x
=>4x = 6z-3y(二）
结合（一）（二）
6z-3y = 2y+z
5z = 5y
z = y
代入（二）
4x = y ×6 - 3y
4x = 3y
x = 3/4y
3/4 y + y + y = 27
3y + 4y + 4y = 108
11y = 108
y = 108/11
z = 108/11
x = 81/11

我会，没有分谁帮你答啊

解,将第一个等式分解成两个等式得
x+y/2=z+x/3```````1
z+x/3=y+z/4```````2
x+y+z=27``````````3
由1得:3y=4z-x`````4
由2得:3y=4x+z`````5
3*3得:3y=81-3x-3z`6
由4,5得:4z-x=4x+z
3z=5x
由5,6得4z-x=...

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先通分,12x+6y=12z+4x=12y+3z
即4x+3y-6z=0
4x-12y+9z=0
4x-2y-z=0
化简得y=z
由4x-3y=0和x+2y=27得
x=81/11,y=z=108/11

先通分。6x+6y=4z+4x =3y+3z
2x+6y-4z=0
x+3y-2z=0 因为x+y+z=27
所以3z-2y=0

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