4a+2b+c=5,-b/2a=1,(4ac-b^2)/4a=3,求ABC的值,要步聚,忘了,

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4a+2b+c=5,-b/2a=1,(4ac-b^2)/4a=3,求ABC的值,要步聚,忘了,

4a+2b+c=5,-b/2a=1,(4ac-b^2)/4a=3,求ABC的值,要步聚,忘了,
4a+2b+c=5,-b/2a=1,(4ac-b^2)/4a=3,求ABC的值,要步聚,忘了,

4a+2b+c=5,-b/2a=1,(4ac-b^2)/4a=3,求ABC的值,要步聚,忘了,
由,-b/2a=1得
b=-2a;
所以,带入4a+2b+c=5,得
4a-4a+c=5;
c=5;
带入(4ac-b^2)/4a=3,得
(20a-4a^2)/4a=3;
解方程得
a=0或a=2;
b=0或b=-4;
c=5

4a+2b+c=5 (1)
-b/2a=1 (2)
(4ac-b^2)/4a=3 (3)
(3)化简得:c-(b/2)(b/2a)=3 (4)
(2)代入(4)得:c+b/2=3,所以c=3-b/2
由(2)得a=-b/2
将上面两式代入(1)得:
4*(-b/2)+2b+(3-b/2)=5<...

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4a+2b+c=5 (1)
-b/2a=1 (2)
(4ac-b^2)/4a=3 (3)
(3)化简得:c-(b/2)(b/2a)=3 (4)
(2)代入(4)得:c+b/2=3,所以c=3-b/2
由(2)得a=-b/2
将上面两式代入(1)得:
4*(-b/2)+2b+(3-b/2)=5
解得b=-4
所以a=-b/2=2,c=3-b/2=5
a是分母不可能=0

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