1/(1*2*3)+1/(2*3*4)+1/(3*4*5)+…+1/(98*99*100)求详细过程

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/05 04:11:58
1/(1*2*3)+1/(2*3*4)+1/(3*4*5)+…+1/(98*99*100)求详细过程

1/(1*2*3)+1/(2*3*4)+1/(3*4*5)+…+1/(98*99*100)求详细过程
1/(1*2*3)+1/(2*3*4)+1/(3*4*5)+…+1/(98*99*100)求详细过程

1/(1*2*3)+1/(2*3*4)+1/(3*4*5)+…+1/(98*99*100)求详细过程
1/(1*2*3)+1/(2*3*4)+1/(3*4*5)+…+1/(98*99*100)
=(1-1/2-1/3)+(1/2-1/3-1/4)+(1/3-1/4-1/5)+.1/98-1/99-1/100
=1-1/100
=99/100
备注：1/(1*2*3)=1-1/2-1/3
祝国庆节快乐!

1+2+3+4+1 1 2 3 4 1 2 3 4 1 2 3 4 1,2,3,4, 1 2 3 4 1 2 3 4 1,2,3,4, 1,2,3,4, 1,2,3,4, 1,2,3,4, 1 2 3 4 1,2,3,4, 1,2,3,4, 1,2,3,4, 1、2、3、4 1+2+3×4 1,2,3,4