（2)(x-2)(x+2)-(x+1)(x-3)(3) (ab+1)²-(ab-1)²(4)（2x-y)²－4(x-y)(x+2y)

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/09 09:50:30
（2)(x-2)(x+2)-(x+1)(x-3)(3) (ab+1)²-(ab-1)²(4)（2x-y)²－4(x-y)(x+2y)

（2)(x-2)(x+2)-(x+1)(x-3)(3) (ab+1)²-(ab-1)²(4)（2x-y)²－4(x-y)(x+2y)
（2)(x-2)(x+2)-(x+1)(x-3)
(3) (ab+1)²-(ab-1)²
(4)（2x-y)²－4(x-y)(x+2y)

（2)(x-2)(x+2)-(x+1)(x-3)(3) (ab+1)²-(ab-1)²(4)（2x-y)²－4(x-y)(x+2y)
（2)(x-2)(x+2)-(x+1)(x-3)
=x²-4-(x²-2x-3)
=x²-4-x²+2x+3
=2x-1
(3) (ab+1)²-(ab-1)²
=(ab+1+ab-1)(ab+1-ab+1)
=2(2ab)
=4ab
(4)（2x-y)²－4(x-y)(x+2y)
=4x²-4xy+y²-4(x²+xy-2y²)
=4x²-4xy+y²-4x²-4xy+8y²
=-8xy+9y²

这个不是初一的吧，分解因式，初二的

化简？

很简单的题你都不会做？我也是初一的。。。呵呵

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