1.已知Ax^2n+1=x^3n(x≠0),求A的值 2.36^x÷6^x 3.若（x^n+1)^2(x^2)^n-1=x^4,则n=

1.已知Ax^2n+1=x^3n(x≠0),求A的值 2.36^x÷6^x 3.若（x^n+1)^2(x^2)^n-1=x^4,则n=
1.已知Ax^2n+1=x^3n(x≠0),求A的值 2.36^x÷6^x 3.若（x^n+1)^2(x^2)^n-1=x^4,则n=

1.已知Ax^2n+1=x^3n(x≠0),求A的值 2.36^x÷6^x 3.若（x^n+1)^2(x^2)^n-1=x^4,则n=
1A=X^3n-1/x^2n ,x=1时,A=0,当x=-1时,A=0或者-2.这道题怪怪的.
2.6^x
3n-1次方还是先n次方然后减一?n=1.