求函数f(x)=cos^2(x-pai/12)+sin^2(x+pai/12)-1的周期教我一下过程,高一的基本忘了,公式最好也列出来!谢谢了,各位大虾!

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/03 02:50:51
求函数f(x)=cos^2(x-pai/12)+sin^2(x+pai/12)-1的周期教我一下过程,高一的基本忘了,公式最好也列出来!谢谢了,各位大虾!

求函数f(x)=cos^2(x-pai/12)+sin^2(x+pai/12)-1的周期教我一下过程,高一的基本忘了,公式最好也列出来!谢谢了,各位大虾!
求函数f(x)=cos^2(x-pai/12)+sin^2(x+pai/12)-1的周期
教我一下过程,高一的基本忘了,公式最好也列出来!
谢谢了,各位大虾!

求函数f(x)=cos^2(x-pai/12)+sin^2(x+pai/12)-1的周期教我一下过程,高一的基本忘了,公式最好也列出来!谢谢了,各位大虾!
cos²x=(1+cos2x)/2
sin²x=(1-cos2x)/2
所以f(x)=[1+cos(2x-π/6)]/2+[1-cos(2x+π/6)]/2-1
=1/2[cos(2x-π/6)-cos(2x+π/6)]
=1/2[(cos2xcosπ/6+sin2xsinπ/6)-(cos2xcosπ/6-sin2xsinπ/6)]
=sin2xsinπ/6
=(1/2)sin2x
所以T=2π/2=π

The rockets to Alan didn't interest not only retired as Bryant win gambling
Beijing time on July 6, the Houston chronicle columnist Jonathan answered the blog fegan - the new questions, fans of th...

全部展开

The rockets to Alan didn't interest not only retired as Bryant win gambling
Beijing time on July 6, the Houston chronicle columnist Jonathan answered the blog fegan - the new questions, fans of the target is that the rockets fagan inside players, they won't go chasing ray Allen. In chasing Chris bosh, when the rockets this behavior, so that is a kind of gambling, but if not, then the gambling as Bryant won only retirement --
The rockets fans: for ray Allen interested? If Alan willing to accept his middle contract, can become the "sixth man".
Fegan: I think ray Allen will return to the celtics. The rockets won't chase him, even if they can't get bosh, they that contract to a big middle.
Fan: if the rockets got,Nba Jersey, then they can bosh beat the lakers in the western conference finals? I think the rockets still lack the player has playoff experience, they should add some kind of role players.
Rockets need not add fagan: role players, they just need another superstar, a potential partner and yao Ming, the star bosh and would be a good partner. You can see the two seasons ago: in the playoffs in the first round, the rockets beat a top team in western, and then put the lakers in round 2 youyet tiebreak. Then again they have got Kevin Martin, trevor ariza, Patrick Paterson, Jordan - hill and chase, and Aaron - bardeen Brooks has also become the fastest player, the progress of alliance and they lost only RON artest and Carl landry. If yao can stay healthy, why not become a rocket championship contenders? Don't they wait to Bryant retirement? They are good, they can play better. In order to become better,Wholesale Jerseys Factory, the rockets must bear the risk of trade, if they can undertake such transactions.
If the rockets fans in mid-season trade t-mac will, so now they will have enough space to direct salary with bosh.
But the rockets won't have fagan Kevin Martin, Jordan - hill and two draft picks in the future.
Fan: I just want to know, considering the past several days in the league players get free contract,Authentic Nba Jerseys, you think luis scola and kyle - los repower how get a contract? In addition, I very like josh Howard, you think he is suitable for the rockets?
Fegan: I don't think the way for the rockets play Howard,Sport Jerseys, although he is in good condition of certain efficiency. Scola and red is restricted free agent, I can't guess how they can get the contract. Scola seems can at least get terms, and as the middle of this red guard seems to always get that contract.

收起

f(x)=cos^2(x-pai/12)+sin^2(x+pai/12)-1
=[1+cos(2x-π/6)]/2+[1-cos(2x+π/6)]/2-1
=[cos(2x-π/6)-cos(2x+π/6)]/2
=(sin2x)/2
所以最小正周期为π
这里主要公式是二倍角公式和两角和差公式,都是常规公式,书上有

已知函数f(x)=cos^2(pai/4+x)cos^2(pai/4-x),则f(pai/12)等于 函数f(x)=sin(pai/2+x)cos(pai/6-x)的最大值 已知函数f(x)=cos(2x-pai/3)+2sin(x-pai/4).sin(x+pai/4)求函数在区间[-pai/12,pai /12]上最大值和最小值 已知函数f(x)=sin(2x+pai/6)+sin(2x-pai/6)+2cos^2x,求f(x)的最大值和最小正周期 已知函数f(x)=(1+根号2cos(2x-(pai/4)))/sin(x+(pai/2)),求f(x)定义域 已知函数f(x)=2sin(x+pai/6)-2cos,x属于[pai/2,pai].若sinx=4/5求f(x)的值,求函数f(x)的值域 求函数y=sin(pai/2+x)*cos(pai/6-x)的最大值和最小值 已知函数fx=根号2cos(x-pai/12) (1)求f(-pai/6) (2)若cosa=3/5,a属于(3pai/2,2pai),求f(a+7pai/12) 化简!f(x)=sin(pai-x)cos(3/2pai+x)+sin(pai+x)sin(3/2pai-x)求单调减区间。 已知函数f(x)=2cos x sin(x+pai/6)-sin^2x+cos^2x.已知函数f(x)=2cos x sin( x + pai/6 )- sin^2x + cos^2x.(1)求函数f(x)的单调递增区间;(2)当x属于[-pai/12,pai/6]时,求函数 f(x) 的最大值、最小值及相应的 x 的值.想知道 F(x)=[cos^3x-sin^2(x+pai)-cos(x+pai)+1]/[1+cos^2(7pai+x)+cos(-x),化简并求F(5pai/3) f x =sin(pai*x/4-pai/6)-2(cos pai*x/8)^2+1 高一数学已知函数f(x)=cos(2pai-x)cos(pai/2-x)-sin^2x求函数f(x)的最小正周期和单调增区间 导函数f'(x)=2cos(2x+pai/3)的原函数是什么 已知函数f(x)=cos∧2(x+pai/12)+(1/2)sin2x1,求f(x)的最值 2.求f(x)的单调增区间 设函数f(x)=cos(2x-pai/3)+2(sinx)* 求最大值和最小正周期* =平方 求函数y=2cos(x+pai/4)cos(x-pai/4)+根号3sin2x的值域 求函数f(x)=2cos^2x+3sinx在-pai/2到pai/2上的最值