作业帮[（x+2y-3/2)(x-2y+3/2)+2y(2y-3)+(2^－²/3)] /(-3x)^－¹,其中x=-1,y=2007/2006
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/26 16:48:09
![[（x+2y-3/2)(x-2y+3/2)+2y(2y-3)+(2^－²/3)] /(-3x)^－¹,其中x=-1,y=2007/2006](/uploads/image/z/12785423-23-3.jpg?t=%5B%EF%BC%88x%2B2y-3%2F2%29%28x-2y%2B3%2F2%29%2B2y%282y-3%29%2B%282%5E%EF%BC%8D%26sup2%3B%2F3%29%5D+%2F%28-3x%29%5E%EF%BC%8D%26sup1%3B%2C%E5%85%B6%E4%B8%ADx%3D-1%2Cy%3D2007%2F2006)
[（x+2y-3/2)(x-2y+3/2)+2y(2y-3)+(2^－²/3)] /(-3x)^－¹,其中x=-1,y=2007/2006
[（x+2y-3/2)(x-2y+3/2)+2y(2y-3)+(2^－²/3)] /(-3x)^－¹,其中x=-1,y=2007/2006
[（x+2y-3/2)(x-2y+3/2)+2y(2y-3)+(2^－²/3)] /(-3x)^－¹,其中x=-1,y=2007/2006
原式=｛[x2-(2y-3／2）2]+4y2-6y＋1／12｝÷（1／3）
=（x2-4y2+6y-9／4+4y2-6y+1／12）÷（1／3）
=（x2-9／4+1／12）×3=－3.5
其实这道题跟y一点关系都没有
很简单嘛
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