NO.1 (log3 2 + log9 2) (log4 3 + log8 3) NO.2 (lg5)的平方 + (lg50 乘 lg2)NO.3 [(1 - log6 3)的平方 + (log6 2 乘 log6 18)] 除 log6 4第一题你做错了,是5/4

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/08 10:31:02
NO.1 (log3 2 + log9 2) (log4 3 + log8 3) NO.2 (lg5)的平方 + (lg50 乘 lg2)NO.3 [(1 - log6 3)的平方 + (log6 2 乘 log6 18)] 除 log6 4第一题你做错了,是5/4

NO.1 (log3 2 + log9 2) (log4 3 + log8 3) NO.2 (lg5)的平方 + (lg50 乘 lg2)NO.3 [(1 - log6 3)的平方 + (log6 2 乘 log6 18)] 除 log6 4第一题你做错了,是5/4
NO.1 (log3 2 + log9 2) (log4 3 + log8 3)
NO.2 (lg5)的平方 + (lg50 乘 lg2)
NO.3
[(1 - log6 3)的平方 + (log6 2 乘 log6 18)] 除 log6 4
第一题你做错了,是5/4

NO.1 (log3 2 + log9 2) (log4 3 + log8 3) NO.2 (lg5)的平方 + (lg50 乘 lg2)NO.3 [(1 - log6 3)的平方 + (log6 2 乘 log6 18)] 除 log6 4第一题你做错了,是5/4
1.原式
=(log3(2)+1/2log3(2))*(2log2(3)+3log2(3))
=3/2*5*log2(3)*log3(2)
=15/2
2.因为(lg5)^2+lg2*lg50
=(lg5)^2+lg2*lg(5*10)
=(lg5)^2+lg2*(lg5+lg10)
=(lg5)^2+lg2(lg5+1)
=lg5*(lg2+lg5)+lg2
=lg5*lg10+lg2
=lg5+lg2=lg(2*5)=lg10=1
3.[(1-log6(3))^2 + log6(2) × log6(18)]÷log6(4)
=[log6(2)^2 + log6(2) × (log6(3)+1)]÷2log6(2)
=(log6(2)+log6(3)+1)/2
=(1+1)/2
=1