f(x)=2x-cosxx=0.5

函数f（x）=sinx-根号3cosxX属于【—派,0】的单调递增区间怎么依照题意得f(x)=2sin(x-派/3）?函数f（x）=sinx-根号3cosxX属于【—派,0】的单调递增区间怎么依照题意

limx^2/根号√1+XsinX-根号√cosXx->0limx^2/根号√1+XsinX-根号√cosXx->0limx^2/根号√1+XsinX-根号√cosXx->0用洛彼达法则:limx^2

计算：Lim|sinx|/√1-cosxx→∞2|cos(x/2)|有极限吗?有,怎样证计算：Lim|sinx|/√1-cosxx→∞2|cos(x/2)|有极限吗?有,怎样证计算：Lim|sinx|

计算lim（x-0）[1-cosx]/[xln(1+x)]lim1-cosxx-0------xln(1+x)计算lim（x-0）[1-cosx]/[xln(1+x)]lim1-cosxx-0----

急任意角的三角比解不等式sinx>=cosxx属于[0,2派]最好有过程呃急任意角的三角比解不等式sinx>=cosxx属于[0,2派]最好有过程呃急任意角的三角比解不等式sinx>=cosxx属于[

f(X)=f(X+2)(xf(X)=f(X+2)(xf(X)=f(X+2)(x-3

f(x)=x/(1+x^2)^0.5求f(f(f(x)))f(x)=x/(1+x^2)^0.5求f(f(f(x)))f(x)=x/(1+x^2)^0.5求f(f(f(x)))f(f(f(x)))=x/

f(x)=x^2+x(xf(x)=x^2+x(xf(x)=x^2+x(x你的条件好像不全吧,请你把题完整的给出来.后面的f(-x)有没有另加条件,比如x>0这个条件?

f(x+2)>=f(x)+2,f(x+3)f(x+2)>=f(x)+2,f(x+3)f(x+2)>=f(x)+2,f(x+3)∵f(x+2)>=f(x)+2,∴f(x+3)≥f(x+1)+2.又∵f(

f(x)是奇函数f(1)=0.5f(x+2)=f(x)+f(2)求f(5)f(x)是奇函数f(1)=0.5f(x+2)=f(x)+f(2)求f(5)f(x)是奇函数f(1)=0.5f(x+2)=f(x

若f(x)满足f(x)-2f(1/x)=x,则f(x)=?若f(x)满足f(x)-2f(1/x)=x,则f(x)=?若f(x)满足f(x)-2f(1/x)=x,则f(x)=?f(x)-2f(1/x)=

若F(x)满足f(x)+2f(1/x)=x,则f(x)=若F(x)满足f(x)+2f(1/x)=x,则f(x)=若F(x)满足f(x)+2f(1/x)=x,则f(x)=f(x)+2f(1/x)=x①那

设函数f(x)满足f(x)+2f(1/x)=x,求f(x)设函数f(x)满足f(x)+2f(1/x)=x,求f(x)设函数f(x)满足f(x)+2f(1/x)=x,求f(x)f(x)+2f(1/x)=

已知f(x)满足2f(x)+f(1/x)=3x,求f(x)已知f(x)满足2f(x)+f(1/x)=3x,求f(x)已知f(x)满足2f(x)+f(1/x)=3x,求f(x)2f(x)+f(1/x)=

F(X)满足F(x)+2f(x分之1)=3X,求f(x)F(X)满足F(x)+2f(x分之1)=3X,求f(x)F(X)满足F(x)+2f(x分之1)=3X,求f(x)把X换成1/X得：f(1/x)+

已知f(x)满足2f(x)+f(1/x)=3x,求f(x)?已知f(x)满足2f(x)+f(1/x)=3x,求f(x)?已知f(x)满足2f(x)+f(1/x)=3x,求f(x)?把1/x当作x带入上

已知f(x)满足2f(x)+f(-x)=-3x+1,求f(x)已知f(x)满足2f(x)+f(-x)=-3x+1,求f(x)已知f(x)满足2f(x)+f(-x)=-3x+1,求f(x)令x=a,得2

f(x)满足:2f(x)-f(1/x)=x+1,求f(x)f(x)满足:2f(x)-f(1/x)=x+1,求f(x)f(x)满足:2f(x)-f(1/x)=x+1,求f(x)

已知f(x)满足f(x)+2f(1/x)=3x,求f(x),已知f(x)满足f(x)+2f(1/x)=3x,求f(x),已知f(x)满足f(x)+2f(1/x)=3x,求f(x),f(x)+2f(1/

f(x)+f((x-1)/x)=2x;x!=0,1;求f(x)f(x)+f((x-1)/x)=2x;x!=0,1;求f(x)f(x)+f((x-1)/x)=2x;x!=0,1;求f(x)我们已知（1）